Is pick 2 > than 6 & 10 in a supposedly even draft?
Only time will tell. Every decision carries some degree of risk.
Yeah it's a tricky one.
We should play our strategy as a two year launch.
Whatever we do really want 10 high picks over that period.
The 8 in 24 that we have expect by tonight plus 1st and 2nd rd next year.
Reckon then a 6/4 split this year into next.
Take the first 6 selections this year and sell off the last two.
Absolutely confident we'll get first round picks for them (perhaps more).
And you never know where they might land - look at us in 23 (hopper) and pies this year (*smile*). more teams will get burnt into 25.
That gives us 6 premium picks this year and 3 first rounders next (plus our 2nd pick which will be start of second).
We can either go again for elite talent.
And/or we'll have a good gauge on Harley Reid by then (out of contract 12 months later).
If he's in play, we can shuffle some again to get him then.
We'll actually be very attractive then. Young emerging talent, heaps of picks, salary cap room to blow anyone else out, ground, big club etc.
Those reasons are why reticent to "lose" picks in two for ones to trade up.
Say we do 6 & 10/11/14 for 2.
That means we either take one less pick this year, or lose a first rounder next ( and who knows where that lands).
Also gives less options into the future.
If north give 25 back that makes it a lot more palatable but suspect that might get traded for caleb daniel today.
"losing" a pick actually has a high opportunity cost.
food for thought.